A. B, C are three different prime numbers less than 20, a, B, C = 30, and a

A. B, C are three different prime numbers less than 20, a, B, C = 30, and a

Because: there are eight primes less than 20: 2, 3, 5, 7, 11, 13, 17 and 19
So: add the three combinations of the eight prime numbers to get the three numbers whose sum is 30: 2 + 11 + 17 = 30
Because a

Given that a, B and C are three prime numbers less than 20, and a + B + C = 30, what are the numbers of a, B and C?

Because: there are eight primes less than 20: 2, 3, 5, 7, 11, 13, 17 and 19
So: add the three combinations of the eight prime numbers to get the three numbers whose sum is 30: 2 + 11 + 17 = 30
Because a

If three prime numbers a, B, C satisfy a + B = C and a < B is known, then a=______ ．

All prime numbers except 2 are odd. According to odd + odd = even, the sum obtained is even, which must not be prime. 2 is even and prime. Only even + odd = odd can prime numbers be obtained. Therefore, three prime numbers a, B, C satisfy a + B = C. If a < B is known, then a = 2. Therefore, the answer is: 2

Three prime numbers a, B, C, C satisfy a + B = C, and a

2+3=5
a=2

Write 18 in two prime forms, there are () different forms. How to choose a.1 B.2 C.3 D.4

There are only 5 + 13 and 7 + 11, so choose B

A is prime, B is prime, a × B = C, C must be ()
1. Odd 2, composite 3, even 4, prime

A is prime, B is prime, a × B = C, C must be (2)
1. Odd 2, composite 3, even 4, prime
Option 2
Total number

Let 2004 be written as the product of several prime numbers. If a, B and C are three of these prime numbers, and a < B < C, then the solution of the system of equations BX − ay = 1ax − CY = − 165 about X and Y is X=______ ，y=______ ．

∵ 2004 = 2 × 2 × 3 × 167, ∵ a = 2, B = 3, C = 167, substituting into the equations, we get 3x − 2Y = 12x − 167y = − 165, and the solution is x = 1y = 1. So the answer is: x = 1, y = 1

The sum of two prime numbers is 24. What is the maximum value of the product of the two prime numbers?
Today!

11 and 13, the product is 143, because the smaller the difference between them, the greater the product

The sum of the three primes is 32, and the maximum product of the three primes is______ ．

Because, if the sum of three prime numbers is 32, it is impossible to be all odd numbers, so there is 2, and 30 is left. Write 30 as the sum of two numbers. The closer the two numbers are, the greater the product should be: 17, 13, so the maximum product of the three prime numbers is: 2 × 13 × 17 = 442, so the answer is: 442

The sum of the three primes is 140. Find the maximum of the product of the three primes

If sum is even, then one must be even, that is, 2
138 ＝ 69＋69＝ 71 + 67
2*71*67=9514