Mr. Wang wrote three integers 2,4,8 on the blackboard. Then he erased a number and added a number, which is more than the sum of the two numbers on the blackboard. For example, he erased 4 and added a number 2 + 8 + 1 = 11. At this time, the number on the blackboard is 2,8,11?

Mr. Wang wrote three integers 2,4,8 on the blackboard. Then he erased a number and added a number, which is more than the sum of the two numbers on the blackboard. For example, he erased 4 and added a number 2 + 8 + 1 = 11. At this time, the number on the blackboard is 2,8,11?

impossible.
Suppose 2007 is just made up, then 2005 + 2006 + 1 = 4012, not 2007, so 2007 is not just made up
Since all the above complement numbers should be greater than 2007 + 2008, of course, it is impossible to make up for them

There are eight numbers 3, 4, 5, 6, 7, 8 and 9 written on the blackboard. Two numbers are deleted at any time, and the sum of these two numbers is added with 3. After several operations, there is only one number left on the blackboard, which is () a, 52 B, 70 C, 73 D, 76 E and 80 (need specific explanation)

73 because your 10 numbers are dead and will not change. How to add them will not change. Then you use 8 numbers four times, and then you will get another 4 numbers, and then you will get 2 numbers by erasing two times. In the middle of the last time, 7 times in total, 3 times in total, 21 numbers in total, 52 = 73

There are five natural numbers written on the blackboard: 1, 3, 5, 6, 7. One operation refers to randomly selecting two numbers and erasing them, and writing their sum on the blackboard
After four times of this operation, there is only one number left on the blackboard and four numbers written on the paper, then the sum of the four numbers is

A number on the blackboard is 22
The sum of the four numbers on the paper is 182