Simplify the evaluation of negative half A-2 (a minus half B to the second power) - (minus three-thirds a minus one-third B to the second power) a = - 1, B = one-third B = two-thirds, not one-third. sent the wrong message. Hee hee hurry up

Simplify the evaluation of negative half A-2 (a minus half B to the second power) - (minus three-thirds a minus one-third B to the second power) a = - 1, B = one-third B = two-thirds, not one-third. sent the wrong message. Hee hee hurry up

-1/2a-2(a-1/2b^2)-(-3/2a-1/3b^2)
=-1/2a-2a+b^2+3/2a+1/3b^2
=-a+4/3b^2
a=-1,b=2/3
Original formula = 1 + 4 / 3x4 / 9
=1+16/27
=43/27

What is the sum of the 101st power of negative two plus the 102nd power of negative two

（-2）^101+(-2)^102
=（-2）^101+(-2)^101*(-2)
=(-2)^101*(1-2)
=-(-2)^101
=2^101

Fractional power reduction of integral a
For example, (a + b) ^ (1 / 2)?
For example, m belongs to R, n belongs to N, simplify (a1 + A2 + a3 +... + an) ^ (1 / M)

The two formulas you give are the simplest forms, so they can't be simplified any more

How to simplify the negative quadratic power of 5?
Please explain the process of the solution! And calculate it! Thank you!
But also explain why this solution Oh!

The negative second power of 5 = the second power of 5 = 1 / 25
The formula is: the - K power of a = 1 / K power of A
The derivation process is as follows: one of the k-th power of a = 1 ﹣ a ^ k = a ^ 0 ﹣ a ^ k = a ^ (0-k) = a ^ (- K)

Simplification: root 8A * 3 power * B4 power * C5 power

√8a^3*b^4*c^5
=2b^2√2a^3**c^5