(2009 * 2010) / (2010 * 2009-2009 ^ 2) simple algorithm

(2009 * 2010) / (2010 * 2009-2009 ^ 2) simple algorithm

（2009×2010）/（2009×（2010-2009）
=（2009×2010）/2009×1
=2010

The square of (a-b) is multiplied by the nth power of (a-b) and divided by the 5th power of (B-A)
emergency

(a-b)^2*(a-b)^n/(b-a)^5
=(a-b)^n/(b-a)^3
=(-1)*(a-b)^(n-3)

Wang Liang and Li Jun are playing a game. In advance, they prepared cards with the following four numbers: (1 / 3) ^ 20, 3 ^ 20, (- 1 / 2) ^ 30, (- 2) ^ 30
They put the cards into a sealed box. The rules of the game are: two people take the cards in turn, and calculate the product of the two numbers they get. It is stipulated that whoever gets the big result wins. The two numbers Wang Liang draws are (1 / 3) ^ 20,3 ^ 20, and the two numbers Li Jun draws are (- 1 / 2) ^ 30, (- 2) ^ 30. At this time, they all think they have won. Please be the referee, who do you think wins, And explain the reason

3^20*（1/3）^20=3^20*3^(-20)=1
(-1/2)^30*(-2)^30=2^(-20)*2^20=1
The two are tied
Hope to help you

-How to add square brackets to the degree of 0 + 4 / 12
It's not - 4 - it's the sign of the opposite of the number you got that night

(- 4 ^ 2 + 12) / 4 + 1 = 0, that is (- 16 + 12) / 4 + 1 = 0