When it floats on the surface of water, half of its volume is immersed in water, and the density of water is p A. The density p / 2 B and buoyancy of the object are mg C. The density of the object is m / a cubic D, and the buoyancy of the object is PGA cubic D Please explain why,

When it floats on the surface of water, half of its volume is immersed in water, and the density of water is p A. The density p / 2 B and buoyancy of the object are mg C. The density of the object is m / a cubic D, and the buoyancy of the object is PGA cubic D Please explain why,

A. Correct, gravity and buoyancy balance, Mg = ρ g (a ^ 3) = 0.5pg (a ^ 3), deduce ρ = P / 2
B. Correct, gravity and buoyancy balance, f buoyancy = g wood = mg
C. Correct. From the density formula M = ρ * (a ^ 3), ρ = m / (a ^ 3)
D. False, f buoyancy = g wood = mg = 0.5pg (a ^ 3)

The volume and density of a wood block are 200cm and 0.8 × 10 kg / m respectively. When the wood block floats on the water surface and is still, how large is the volume immersed in the water?

1. Because the density of wood block is less than that of water, the wood block floats instead of suspending
2. Because the wood is floating, so g = f floating, so p wood V wood g = P water V row G
That is 800 * 200 = 1000 * V row
Row v = 160 cm3
That is, the volume immersed in water is 160 cubic centimeters
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There is a piece of ice with a volume of 0.05 cubic meters. After it completely melts into water, what is the volume of water?
It should be said that after the ice melts into water, m ice = m water. So first find out how much m water is, and then find out v water according to v = m / P of water. What's wrong?

There is a piece of ice with a volume of 0.05 cubic meters. After it completely melts into water, what is the volume of water?
0.05m^3*0.9*10^3kg/m^3=45kg
The volume of 45kg water is 0.045m ^ 3