A cube iron block with a mass of 7.8kg is placed in the center of a horizontal tabletop with an area of 0.5m & sup2;, and the following questions are asked: (1) how much PA is the pressure of the iron block on the tabletop? (2) how much PA is the pressure of the iron block on the tabletop if a force of 12n is applied on the iron block along the vertical direction? (ρ iron = 7.8 × 10 & sup3; kg / M & sup3;

A cube iron block with a mass of 7.8kg is placed in the center of a horizontal tabletop with an area of 0.5m & sup2;, and the following questions are asked: (1) how much PA is the pressure of the iron block on the tabletop? (2) how much PA is the pressure of the iron block on the tabletop if a force of 12n is applied on the iron block along the vertical direction? (ρ iron = 7.8 × 10 & sup3; kg / M & sup3;

P = f / S = g / S = mg / S = 7.8 * 9.8 / 0.1 =
p=F/S=（G+F）/S=（7.8*9.8+12）/0.1=?

The side length of a cube aluminum block is 1 DM, which is placed in the middle of a table with an area of 0.6 m square. What is the pressure of the aluminum block on the table?
(P = 2.7 * 10 to the third power, kg / m to the third power)

Mass m = PV = 2.7kg
G = mg = 2.7 * 10 = 27 n (G is 10)
∵ bottom area of aluminum block = 0.01M

How much pressure (g = 10N / kg) does a cube iron block with side length of 0.1M put in the center of a horizontal table with an area of 1m square meter
The cube iron with side length of 0.1 meters is placed in the center of the horizontal desktop with an area of 1 square meter. How much pressure does the desktop suffer (g = 10N / kg) P iron = 7.9 * 10 cubic kg / m. The Great Xia, help

Volume times density = pressure 0.1x10-3x7.9 = 0.79kg
Pressure = 0.79kg/m2