Two metal cylinders stand on the horizontal table, the ratio of their bottom area is 8:9, the ratio of their density is 9:8, and the ratio of the pressure on the table is 3:2. Then the ratio of the height of the two metal cylinders is 8:9______ ．

Two metal cylinders stand on the horizontal table, the ratio of their bottom area is 8:9, the ratio of their density is 9:8, and the ratio of the pressure on the table is 3:2. Then the ratio of the height of the two metal cylinders is 8:9______ ．

The pressure of cylinder on horizontal table is: P = FS = GS = MGS = ρ VGS = ρ SHGs = ρ GH, because ρ 1: ρ 2 = 9:8, P1: P2 = 3:2, so according to h = P ρ g, we can get: H1H2 = P1 ρ 1gp2 ρ 2G = p1p2 × ρ 2, ρ 1 = 32 × 89 = 43

When a rectangular metal block with a density of ρ is placed flat on the horizontal ground, the pressure on the ground is p. if the rectangular metal block is cut half along the vertical direction, the density of the remaining half of the metal block is (), and the pressure on the horizontal ground is ()

If the cuboid metal block is cut in half along the vertical direction, the density of the remaining metal block remains unchanged and the pressure on the horizontal ground remains unchanged

When a cuboid is placed on a horizontal table, its density is known to be p, its height is h, and its bottom area is s

Pressure = P * h * s
Pressure = pressure / S = P * h