If the mass of a cube with a side length of 10 cm is 0.6 kg, what is the density of the cube;

If the mass of a cube with a side length of 10 cm is 0.6 kg, what is the density of the cube;

The mass of wood block is 0.6kg, which is divided by the volume of cube by 0.001M. The answer is 600kg / m

As shown in the figure, a solid cube wood block with a side length of 10cm, with a density of 0.6 × 103kg / m3, is still in a container with enough water, and the upper and lower bottom surfaces are parallel to the water surface. Calculate: (1) the mass of the block; (2) the buoyancy of the block in the water; (3) the volume of the block immersed in the water; (4) the pressure of water on the bottom surface of the block. (g = 10N / kg)

(1) V = (0.1M) 3 = 10-3m3, using ρ = MV, it is obtained that: M = ρ v = 0.6 × 103kg / m3 × 10-3m3 = 0.6kg; (2) from the question, we can know that the object is floating and in equilibrium, then f floating = g = mg = 0.6kg × 10N / kg = 6N; (3) from F floating = ρ GV, then V row = f floating ρ g = 6n1.0 × 103kg / m3 × & nbsp; The results show that: 10N / kg = 6 × 10-4m3; (4) depth h = V row s = 6 × 10 − 4m310 − 2M2 = 0.06m, then using the pressure formula P = ρ GH, substituting the data, P = 1.0 × 103kg / m3 × 10N / kg × 0.06mp = 0.6 × 103pa; answer: (1) the mass of wood block is 0.6kg; (2) the buoyancy of wood block in water is 6N; (3) the volume of wood block immersed in water is 6 × 10-4m3; (4) the pressure of water on the bottom surface of wood block is 0.6 × 103pa; (4) the pressure of water on the bottom surface of wood block is 0.6 × 103pa;

Put two solid cubes A and B made of the same material on the horizontal table top, and the pressure of a and B on the table top is P1 and P2 respectively. Put a on top of B, as shown in the figure, then the pressure of B on the table top is ()
A. p1+p2B. p12+p22C. p13+p23p22D. p13+p23p12

Let the density of two cubes be ρ, and the side lengths be L A and L B, respectively. The pressure of a on the table is: P1 = g a, s a = ρ GL3 a, L2 a = ρ GL1 a, l a = P1 ρ g. similarly, l b = P2 ρ G. when a is placed on B, the pressure of B on the table is: P = ρ GL3 a + ρ GL3 B, L2 B = ρ g (P1 ρ g) 3 + ρ g (P2