The cylinder with the height of 10 cm is erected on the horizontal table. The pressure of copper block on the table is calculated (P (copper) = 8.9 × 10 cubic kg / M cubic)

The cylinder with the height of 10 cm is erected on the horizontal table. The pressure of copper block on the table is calculated (P (copper) = 8.9 × 10 cubic kg / M cubic)

P=G/S=pVg/S=pShg/S=pgh=8.9x10^3x10x10^(-2)=8.9x10^2pa

What is the pressure of a 10 cm high iron cylinder on a horizontal table? (P iron = 7.9x10 third power kg / M & SUP)

P = density * g * h
=9.8n/kg PFE = 7.9x10 cubic kg / M & sup3; H = 0.1M
P = 7.9x10 cubic kg / M & sup3; * g * 0.1M = 7900g (n / m2)
If G is to be substituted, then G is to be substituted
It should be like this. If there is anything wrong, please forgive me

A cylinder with density ρ, height h and bottom area s. It is proved that the pressure of the cylinder on the horizontal ground has nothing to do with the bottom area of the cylinder

It is proved that: the bottom area of the cylinder is s, the height is h, the volume is v = sh, ∵ ρ = MV; the mass of the cylinder is m = ρ v = ρ sh; the pressure of the cylinder on the horizontal ground is f = g = ρ SHG; the pressure of the cylinder on the ground is p = FS = ρ SHGs = ρ GH. It can be seen that the pressure of the cylinder on the ground has nothing to do with the bottom area