When x = ~ 2, a times the fifth power of x plus B times the third power of x plus CX minus 1 equals 5? Please help... Urgent!

When x = ~ 2, a times the fifth power of x plus B times the third power of x plus CX minus 1 equals 5? Please help... Urgent!

Let f (x) = ax ^ 5 + BX ^ 3 + CX-1
G (x) = f (x) + 1 = ax ^ 5 + BX ^ 3 + CX is an odd function
f(-2)=5
g(-2)=f(-2)+1=6
g(2)=-g(-2)=-6
f(2)=g(2)-1=-6-1=-7

What is the result of the third power / (2y-2x) of [(X-Y) to the power of M * (Y-X) to the power of 2]?

-1/2*（x-y）^(3m+5)

If the m-th power - (n-1) x + 1 of the polynomial 3x is a quadratic binomial of X, the value of M and N can be obtained
Write down the reasons

Because the m-th power of 3x minus (n-1) x + 1 is a quadratic binomial of X
And one is already one
So, because the m-th power minus (n-1) x of 3x can only be quadratic one term, so n-1 = 0, n = 1
M = 2 if m power of 3x is quadratic
To sum up
m=2
n=1
Hope to help you

If the integer MNM is greater than or equal to N and M3 + N3 + 1 = 4Mn, then M-N

-mn（m-n）²+m（n-m）^3
=-mn（m-n）²-m（m-n）^3
=-m(m-n)²(m-n+n)
=-[m(m-n)]²