When a ＜ 0, B ＜ 0 - A + 2 √ ab-b is reduced to what?

When a ＜ 0, B ＜ 0 - A + 2 √ ab-b is reduced to what?

It can be reduced to (√ - A + √ - b) ^ 2

If ABC > 0, a / C | a |, simplify | a + C | + | B + C | - | a-b|
There has to be a process

If ABC > 0, there must be two negative numbers or all positive numbers
a/c

What is a ^ 2 + B ^ 2 + C ^ 2-ab-bc-ac after simplification?

=[(a-b)²+(b-c)²+(c-a)²]/2

How to reduce AB / (a + b) + C to ab + AC + BC
emergency

ab/(a+b)+c
=ab/(a+b)+c(a+b)/(a+b)
=(ab+ac+bc)/(a+b)
If we want to simplify to ab + AC + BC, we have to guarantee a + B = 1

The logic function y = ab '+ b'c'd' + abd + a'b'cd 'is simplified
If you can help draw the logic diagram of NAND gate. Thank you
Can you give me the steps? This "right and wrong" means,

Y = ab '+ b'c'd' + abd + a'b'cd '= a (B' + BD) + b'd '(C' + Ca) = ab '+ AD + b'd'c' + b'd'a '= B' (a + a'd ') + AD + b'd'c' = ab '+ b'd' + AD + b'd'c '= ab' + b'd '+ AD + b'd'c' = ab '+ AD + (1 + C') b'd '= ab' (D + D ') + AD + b'd' = ab '(D + D')

Simplifying logic function f = AB + ABC '+ abd with formula method

Simplifying logic function f = AB + ABC '+ abd with formula method
F = AB + ABC '+ abd = AB (1 + C' + D) = AB (∵ 1 + any variable = 1)

Simplifying logic function f = (a + B + C) (a '+ B' + C ')
Reduced to the simplest and or expression

f=(a+b+c)(a'+b'+c')
=aa'+ab'+ac'+bb'+ba'+bc'+ca'+cb'+cc'
=ab'+ac'+ba'+bc'+ca'+cb'
=aXORb+bXORc+aXORc
XOR is XOR

Logic function simplification (a XOR b) XOR (C XOR d)

"♁" represents the "XOR" symbol, which is in line with the web page on the mobile phone. Can you see it? XOR: a ♁ (a) a ♁b = AB & 35; (39; + A & 35; + a ♁ "♁": a