Let a, B, C opposite the three interior angles of △ ABC, if its area s = C ^ 2 - (a-b) ^ 2, then Tan (C / 2) =?

Let a, B, C opposite the three interior angles of △ ABC, if its area s = C ^ 2 - (a-b) ^ 2, then Tan (C / 2) =?

tan(c/2)=tan(180-A-B)=tan(A+B)
cosA=(b^2+c^2-a^2)/2bc
S=(bcsinA)/2

In △ ABC, ABC is the opposite side of angles a, B and C, and 4cosc * sin ^ 2 * C / 2 + cos2c = 0. If 3AB = 25-c ^ 2, find the maximum area of ABC

∵ 4cosc [sin (C / 2)] ^ 2 + cos2c = 0, ∵ 2cosc (1-cosc) + 2 (COSC) ^ 2-1 = 0, ∵ 2cosc-1 = 0, ∵ COSC = 1 / 2, ∵ C is an acute angle, ∵ sinc = √ 3 / 2

On the inequality of X (- X & # 178; + x-1) (2x & # 178; - 6x + 9 / 2)

Classified discussion
1. (- X & # 178; + x-1) > 0 or (2x & # 178; - 6x + 9 / 2)

A car drives from the east to the West. After a journey, it is 210 kilometers away from the west, and then 20% of the whole journey. At this time, the ratio of the distance traveled to the distance not traveled is 3:2. How many kilometers are there between the East and the west?

Suppose the distance between the East and the west is x km, we can get: & nbsp; x-210 + 20% x = 35x, x-210 + 0.2x = 0.6x, & nbsp; 1.2x-210 = 0.6x, & nbsp; 1.2x-0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 3

A car runs from a place to B place. After a journey, it is 210 kilometers away from B place, and then it runs 20% of the whole journey. At this time, the ratio of what has been done and what has not been done is 3:2. How many kilometers is the distance between a and B places?

210/(20%+2/(3+2))=350

A car drives from the east to the West. After a journey, it is 210 kilometers away from the west, and then 20% of the whole journey. At this time, the ratio of the distance traveled to the distance not traveled is 3:2. How many kilometers are there between the East and the west?

Let x-210 + 20% x = 35x, x-210 + 0.2x = 0.6x, & nbsp; 1.2x-210 = 0.6x, & nbsp; 1.2x-0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 350. A: the East and West cities are 350 km apart

A car drives from the east to the West. After a journey, it is 210 kilometers away from the west, and then 20% of the whole journey. At this time, the ratio of the distance traveled to the distance not traveled is 3:2. How many kilometers are there between the East and the west?

Suppose the distance between the East and the west is x km, we can get: & nbsp; x-210 + 20% x = 35x, x-210 + 0.2x = 0.6x, & nbsp; 1.2x-210 = 0.6x, & nbsp; 1.2x-0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 3

A car drives from the east to the West. After a journey, it is 210 kilometers away from the west, and then 20% of the whole journey. At this time, the ratio of the distance traveled to the distance not traveled is 3:2. How many kilometers are there between the East and the west?

Suppose the distance between the East and the west is x km, we can get: & nbsp; x-210 + 20% x = 35x, x-210 + 0.2x = 0.6x, & nbsp; 1.2x-210 = 0.6x, & nbsp; 1.2x-0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 3

A car goes from place a to place B. after a long journey, it is 180 km away from place B, and then 20% of the whole journey. At this time, the distance between the already traveled and the never traveled is different
The ratio is 3: how many kilometers does the car have to travel to get to B? The best is arithmetic

2/（2+3）*100%=40%
Total distance = 180 / (20% + 40%) = 300km
OK: 300 * 3 / (2 + 3) = 180km
In addition: 300-180 = 120km
A: it will take 120 kilometers for the car to reach the second place

A car drives from the east to the West. After a journey, it is 210 kilometers away from the west, and then 20% of the whole journey. At this time, the ratio of the distance traveled to the distance not traveled is 3:2. How many kilometers are there between the East and the west?

Suppose the distance between the East and the west is x km, we can get: & nbsp; x-210 + 20% x = 35x, x-210 + 0.2x = 0.6x, & nbsp; 1.2x-210 = 0.6x, & nbsp; 1.2x-0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.6x = 210, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 3