In △ ABC, the lengths of three sides are positive integers a, B and C respectively, and B ≥ A. if B = 4 and C = 6, how many triangles are there

In △ ABC, the lengths of three sides are positive integers a, B and C respectively, and B ≥ A. if B = 4 and C = 6, how many triangles are there

There are two such triangles. A = 3 or 4

Given the positive integers a, B, C, a 〈 B 〈 C, and the maximum value of C is 6, ask if there is a triangle with ABC as the length of three sides
Given the positive integers a, B, C, a 〈 B 〈 C, and the maximum value of C is 6, is there a triangle with ABC as the length of three sides? If so, how many triangles can be formed at most? If not, explain the reason

The length of three sides can be
2,3,4
2,4,5
2,5,6
3,4,5
3,4,6
3,5,6
Four, five, six, so seven

It is known that the sum of two times of angle B and angle a in triangle ABC is 20 times greater than three times of angle c, and angle c is less than angle A and less than angle B. if the degree of angle c is an integer, how many degrees is angle c equal to

According to the meaning of the title, if 2 * angle B + angle a = 3 * angle c + 20, then angle B + (180 angle c) = 3 * angle c + 20, that is, angle c = 40 + angle B / 4
Because angle c is less than angle A and less than angle B, angle B is greater than 180 degrees, that is, angle B is greater than 60 degrees
Because the degree of angle c is an integer, the condition of degree of angle B is greater than 60 degrees and is a multiple of 4,
If the angle B is 64 degrees, then the angle c is 56 degrees and the angle a is 60 degrees
Take angle B as 68 degrees, angle c = 57 degrees, angle a = 55 degrees, angle c is greater than angle a, which does not meet the condition
So the angle c is 56 degrees