Given a + B = 4N + 2, ab = 1, if the square of 19 + 147ab + 19b is 2009, then n=

Given a + B = 4N + 2, ab = 1, if the square of 19 + 147ab + 19b is 2009, then n=

19a²+147ab+19b²
=19a²+38ab+19b²+109ab
=19(a+b)²+109ab=2009
19(4n+2)²+109×1=2009
(4n+2)²=100
4n+2=±10
n=-3,n=2

Given a + B = 8, ab = 15, find 2A * 2 + 2B * 2

(a+b)²=8²
a²+b²+2ab=64
a²+b²=64-2ab=64+30=34
Double two on both sides
2a²+2b²=68

If AB = 1, B-A = 3, then AB + 2a-2b=

ab+2a-2b=ab+2(a-b)=1+2(-3)=-5

-2a^2b^2+ab^3+a^3b

-2A ^ 2B ^ 2 + AB ^ 3 + A ^ 3B = AB (- 2Ab + B & # 178; + A & # 178;) = AB (a-b) & # 178; I'm glad to answer for you, and wish you progress in your study! [the 1900] team will answer for you. If you don't understand, you can ask! If you agree with my answer, please click the [select as satisfactory answer] button below, thank you! If you have other needs