RT △ ABC, ∠ C = 90 ° and ad = BD, AC = half ab

RT △ ABC, ∠ C = 90 ° and ad = BD, AC = half ab

Because right triangle ABC. Angle c = 90 degrees, ad bisects angle BAC
So angle CAD = angle DAB
Because ad = dB, angle DAB = angle B = angle CAD
Angle B = (180-90) △ 3 = 30
So the angle BAC = 60 degrees
According to a right triangle with an angle of 30 degrees, the bottom edge is equal to half of the hypotenuse
AC = half ab
That's all~

Why is x greater than 0 when y = the negative half power of X?

The negative half power of y = 1 / (√ x)
X is in the root and X is the denominator
So x > 0

The integral of F (x) = the negative half power of X in (0, H)

∫ h x^(-1/2) dx
0
= 2*x^(1/2） |h
|0
=2*h^(1/2）
=2√h

One half of the square equals X
The square of one in two equals X

If you multiply 2x on both sides at the same time, it will become 2x & # 178; = 1, which will solve the problem. The final answer is the root of two