The problem of factorization. Given (x + x1) (x + x2) = x ^ 2 + 2x-15, and x1 ≥ X2, find the value of x1, x2

The problem of factorization. Given (x + x1) (x + x2) = x ^ 2 + 2x-15, and x1 ≥ X2, find the value of x1, x2


(x+x1)(x+x2)=x^2+2x-15
x1+x2=2
x1·x2=-15
∵x1≥x2
∴x1=5,x2=-3



Decomposition factor: M2 (m-1) + 4 (1-m)


m2(m-1)+4(1-m),=(m-1)(m2-4),=(m-1)(m+2)(m-2).



The square of factorization factor-m-1 / 4


-Square of M - 1 / 4 of M
=-(m²+m+1/4)
=-(m+1/2)²