In the experiment of using free falling motion to verify the law of conservation of mechanical energy: if the instantaneous velocity is calculated and verified by measuring the distance between two points on the paper tape, the distance between point 2 and point 4 is S1, the distance between point 0 and point 3 is S2, and the period of tapping is t The relation of T = 0___ ．

In the experiment of using free falling motion to verify the law of conservation of mechanical energy: if the instantaneous velocity is calculated and verified by measuring the distance between two points on the paper tape, the distance between point 2 and point 4 is S1, the distance between point 0 and point 3 is S2, and the period of tapping is t The relation of T = 0___ ．

According to the deduction of uniform variable speed linear motion, the velocity v = s12t when striking point 3, the height h = S2 when the weight falls, when the mechanical energy is conserved, there should be 12m (s12t) 2 = mgs2, thus t = s218gs2; so the answer is: s218gs2

Free falling body formula

First of all, the free falling body can be equal to the uniformly accelerated linear motion with zero initial velocity, so the formulas between them are partly the same
For example: S = 1 / 2gt2
Vt=gt
2gS=Vt2
(Note: the last two here all mean square. Sorry, I'm not very good at it.)

All formulas of free falling body

2) Free falling body motion 1. Initial velocity VO = 0.2. Final velocity VT = GT 3. Falling height h = GT2 / 2 (calculated from VO position downward) 4. Deduction vt2 = 2GH note: (1) free falling body motion is a uniformly accelerated linear motion with zero initial velocity and follows the law of uniformly variable speed linear motion; (2)