We say "two numbers subtract, the difference is less than the subtracted". After learning rational numbers, is this still true? For example

We say "two numbers subtract, the difference is less than the subtracted". After learning rational numbers, is this still true? For example

No, because if it is: a number minus a negative number, then it is equal to the opposite of the negative number
For example: 5 - (- 5) = 5 + 5 = 10
10＞5
So it doesn't work

Is the sum of two rational numbers greater than one of them

If you add a negative number or 0, it's not ＞

Is 1 / 3 rational

Of

Is 1 / 3 rational? Why

Of

Mn is two points on the number axis, which represent rational number - 2,4,1 and 3 / 5 respectively, then the rational number represented by the midpoint a of the line Mn is______ .

You mean - 2.4 and 1 and 3 / 5, right?
If yes
1 and 3 / 5 = 1.6
Then the coordinates of the midpoint a are [1.6 - (- 2.4)] / 2 = 4 / 2 = 2

To know that a is a rational number 1: if the opposite number of a is a, find the value of a 2:10a must be greater than a? Give the reason
Otherwise I won't be able to sleep

If the opposite number of a is a, then a = 0
10A is not necessarily greater than 0
When a = 0, 10a = a
a

It is known that three mutually unequal rational numbers can be written as 0, a, B, or 1, B of a, a + B, and a is greater than B. find the value of a, B

From the known
(1) If a + B = 0, then B = 1, a = - 1
(2) If B / a = 0, then B = 0 does not hold
So to sum up, a = - 1, B = 1

New definition calculation (a △ B = 10A power X 10B power) verification: (m △ n) △ P is equal to m △ (n △ P)

And so on
(m△n)△p=m△(n△p)=10^(m+n+p)

According to the definition of ζ - N, it is proved that the limit of N / (the nth power of a) is equal to 0
According to the definition of ζ - N, it is proved that the limit of N / (the nth power of a) is equal to 0
Note: (definition of ζ - n) let {an} be a sequence of numbers and a be a definite number. For any given positive number ζ, there is always a positive number n, such that when n > n there is an-a

Your topic should be "a" a "a" a "a" a "a" a "a" a "a" a "a" a "a" a "a" is a N-power, a ^ a square of a, a square of a, and C (m, n) represents the number of combinations that choose m from n objects. For n > 1, we have the following: for n > 1, we have the following: |n / A ^ n / A ^ n / A ^ n |a | n = n = n / [1 + (|||||??-1-1) / [(2 / [(n-2) / [(n-2) / [(n-2 / [(n-2) / [(n-2) / [(n-2) / [(n-2) [(n-2) [(n 1) (| - 1) ^] < zeta, As long as n ＞ 1 + 2 / zeta (| a | - 1) ^, we can choose a natural number larger than 1 + 2 / zeta (| a | - 1) ^ as n (this can always be done), then when n ＞ n, there will be | n / A ^ n | < 2 / [(n-1) (| a | - 1) ^] < zeta?

If we define a new operation "*" and a * b = B power of a - a power of B, then 4 * (3 * 2)?

4*（3*2）
=4 * (2 of 3-3 of 2)
=4*（9-8）
=4*1
=Power 1 of 4 - power 4 of 1
=4-1
=3