If the equation AX = BC holds, then the following equation holds: a.abx = ABC b.x = BC c.b-ax = a-bc D.B + AX = B + BC

If the equation AX = BC holds, then the following equation holds: a.abx = ABC b.x = BC c.b-ax = a-bc D.B + AX = B + BC

If the equation AX = BC holds,
Then the following equation holds D.B + AX = B + BC

If the equation ax-2a + 3x = 6 holds for any x, then the value of a is

In fact, it can be seen that a = - 3
ax-2a+3x=6
x(a+3)-(2a+6)=0
So a + 3 = 0 and 2A + 6 = 0
So a = - 3

(1) Find the value range of real number x so that the inequality | (1-abx) / (ax-b) | > 1 satisfies | a|
It's urgent
If the answer is good, I will add points

Similarly, [(AX) ^ 2-1] (b ^ 2-1) > 0 because | a|