A round steel, 1.2m sawed into 2 segments of 1.6m, the surface area increased by 12.56cm, calculate the original volume Come on,

A round steel, 1.2m sawed into 2 segments of 1.6m, the surface area increased by 12.56cm, calculate the original volume Come on,

Four bottom surfaces have been added
The bottom area is: 12.56/4 = 3.14 square centimeter
Volume: 3.14 * 1.2 * 100 = 376.8 square centimeters

A round steel is 1.2 meters long. Now we saw it into two small sections with each section of 0.6 meters long. The surface area is increased by 12.56 square centimeters. The volume of the original round steel can be calculated
I do the answer you help me see in the end right,
1.2m = 120cm
12.56/2*120
=6.28*120
=7536 (square centimeter) thank you. Come on

You're not doing it right!
S table = 12,56 + 120X2 π √ (12,56 / 2 π)
=12,56X120X2π√2
=12,56+=1065,75
=1078,31 (cm2)
Where 12 and 56 are the two bottom areas
√ (12,56 / 2 π) = √ 2 ----- is the radius
2 π √ 2 -- is the circumference of the circle
120X2 π √ 2 = 1065,75 - is the lateral area

A round steel is 1.5 meters long. Now we saw it into two small sections. The sum of the surface area of the two sections is 12.56 square centimeters more than the original. The volume of the original round steel can be calculated

The cross-sectional area of round steel is
12.56 △ 2 = 6.28 square centimeter
1.5 m = 150 cm
The original volume of the round steel is
28 × 150 = 942 square centimeter