What function is f (x) = the square of X in X + 1 Why is the domain of definition (0, ∞) ∪ (- ∞, 0) still related to the origin symmetry? If (0, ∞) ∪ (- ∞, 0) is r, then why change that 0 to 1 and it is not related to the origin symmetry? And how to understand the domain of definition [1. - 1]

What function is f (x) = the square of X in X + 1 Why is the domain of definition (0, ∞) ∪ (- ∞, 0) still related to the origin symmetry? If (0, ∞) ∪ (- ∞, 0) is r, then why change that 0 to 1 and it is not related to the origin symmetry? And how to understand the domain of definition [1. - 1]

Remove its veil -- simplify
f(x)=(x^2+1)/x=x+1/x
Check function
y=ax+b/x
AB > 0 is like a pair of hooks, commonly known as "check function"
ab

Let a > 0, f (x) = the square of X + X, and f (- 1) = - 5

Bring in the special value to get - 1-A ^ 2 = - 5
We can get a = 2 or - 2
Then a = 2