X^3-3X^2-5X-1=0

X^3-3X^2-5X-1=0


X^3-3X^2-5X-1=0
（X+1）(X^2-4X-1)=0
X + 1 = 0 or x ^ 2-4x-1
X = - 1 or x = 2 + radical 5 or x = 2 - radical 5



I want to know the process of solving the cubic equation of one variable
X3-2x2-x=-2


Move item, x ^ 3-2x ^ 2-x + 2 = 0
(X^3-2X^2)-(X-2)=0
X^2(X-2)-(X-2)=0
(X^2-1)(X-2)=0
(X+1)(X-1)(X-2)=0
So X1 = 1, X2 = - 1, X3 = 2
Do not understand the law can give me information, willing to help you answer

Elden Ring Premiere

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