2F (x ^ 2 + x) + F (x ^ 2-3x + 2) = 9x ^ 2-3x-6 find f (60) The definition field of y = f (x) is r, and the above conditions are satisfied for any x belonging to R

2F (x ^ 2 + x) + F (x ^ 2-3x + 2) = 9x ^ 2-3x-6 find f (60) The definition field of y = f (x) is r, and the above conditions are satisfied for any x belonging to R

From 2F (x ^ 2 + x) + F (x ^ 2-3x + 2) = 9x ^ 2-3x-6, we can get: 2F (x ^ 2 + x) + F [(1-x) ^ 2 + (1-x)] = 9x ^ 2-3x-6, let x = 1 / 2 + T, we can get: 2F [(1 / 2 + T) ^ 2 + (1 / 2 + T)] + F [(1 / 2-T) ^ 2 + (1 / 2-T)] = 9 (1 / 2 + T) ^ 2-3 (1 / 2 + T) - 6, we can get: 2F [(1 / 2-T) ^ 2 + (1 / 2-T)] + F [(1 / 2 + T) ^

Equation: 60 * 8 + X / 20 = 2 / 3x

8+3x=40x
8=37x
x=8/37

Equation: 3x = 2 / 8 * 20

60*8+x/20*8=2/3x
480+2/5x=2/3x
2/3x-2/5x=480
4/15x=480
x=480÷4/15
x=1800

Solution equation: 3x (X-2) = 2 (2-x)

From the original equation, (3x + 2) (X-2) = 0, so 3x + 2 = 0 or X-2 = 0, the solution is X1 = - 23, X2 = 2