Try to find out the apparent density, bulk density and water absorption of the stone. Try to find out the apparent density, bulk density and water absorption of the stone? After a stone is completely dried, its mass is 482g. After it is prevented from entering the measuring cylinder filled with water and saturated with water, the water surface rises from 452c3 to 630cm3. After the stone is taken out and the surface water is dried, its mass is 487g. Try to calculate the apparent density, bulk density and water absorption of the stone?

Try to find out the apparent density, bulk density and water absorption of the stone. Try to find out the apparent density, bulk density and water absorption of the stone? After a stone is completely dried, its mass is 482g. After it is prevented from entering the measuring cylinder filled with water and saturated with water, the water surface rises from 452c3 to 630cm3. After the stone is taken out and the surface water is dried, its mass is 487g. Try to calculate the apparent density, bulk density and water absorption of the stone?

Stone water absorption mass = 5g -- 5cm
Stone volume = 630-5-452 = 173 CC
Density = 482 / 173

The volume of a cuboid is 280 cubic centimeters. It is known that the product of its length and width is 56 cubic centimeters. Find the height of the cuboid
We need to work out the formula

280 △ 56 = 5cm

When the height of a cuboid is increased by 5 decimeters, it becomes a cube, and the surface area is increased by 160 square decimeters. What is the volume of the original cuboid?

Length = width = 160 ﹣ 5 ﹣ 4 = 8 decimeters;
So cuboid volume = 5 × 5 × 8 = 200 cubic decimeter;
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When the height of a cuboid is increased by 5 decimeters, it becomes a cube, and its surface area is increased by 160 square decimeters. How many cubic decimeters is the volume of the original cuboid?

The bottom is square
The perimeter is 160 △ 5 = 32 decimeters
So the side length is 32 △ 4 = 8 decimeters
The height is 8-5 = 3 decimeters
So the volume is 8 × 8 × 3 = 192 cubic decimeters

Cut a small rectangle with a volume of 48 cubic centimeters from a cuboid. If the remaining part is just a cube with an edge length of 4 cm, what is the surface area of the original cuboid?

The length of the truncated small rectangle is 48 / 4 / 4 = 3
The original cuboid length is 4 + 3 = 7
The surface area of the original cuboid is (7 * 4) * 2 + (7 * 4) * 2 + (4 * 4) * 2 = 144

Using 18 cuboids with 1 cm long edges to pendulum cuboid a, 3 cm long, 3 cm wide, 2 cm high, 18 cubic cm in volume, B, 9 in length, 2 in width, 1 in height, 18 in volume, what did you find

What's the grade?
It is found that the volume of a cuboid is equal to the length multiplied by the width multiplied by the height

After cutting a small cuboid with a volume of 72 cubic centimeters from a cuboid, the remaining part is a cube with an edge length of 6 cm. What is the surface area of the original cuboid?

72 (6 × 6) = 2 (CM), so the length of the original cuboid is: 2 + 6 = 8 (CM), then the surface area is: (8 × 6 + 6 × 6 + 6 × 8) × 2, = (48 + 36 + 48) × 2, = 132 × 2, = 264 (square cm); a: the surface area of the original cuboid is 264 square cm

Cut off a cuboid with a volume of 32 cubic centimeters, and the rest is just a cube with an edge length of 4 cm, which is the surface of the original cuboid

The cut-off height is: 32 ÷ (4 × 4) = 2cm
The original cuboid is 4cm long, 4cm wide and 6cm high (4 + 2)
Surface area: 4 × 4 × 6 + 4 × 4 × 2 = 128 square cm

After cutting a small cuboid with a volume of 18 cubic decimeters from a cuboid, there is still a cube with an edge length of 3 decimeters to calculate the original surface area of the cuboid

The original surface area of the cuboid = (18 / 3 / 3 + 3) * 3 * 4 + 3 * 3 * 2 = 78 cubic decimeters

After cutting off a small cube with a volume of 18 cubic decimeters from a cuboid, there is still a cube with an edge length of 3 decimeters. What is the original surface area of this cuboid

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18 ÷ (3 × 3) = 2 decimeters
The height of the original cuboid is 2 + 3 = 5 decimeters
The surface area is:
（5×3+5×3+3×3）×2
=39×2
=78 square decimeters
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