Factorization: 2x4-x3-6x2-x + 2

Factorization: 2x4-x3-6x2-x + 2

2x4-x3-6x2-x+2 =x^2(2x^2-x-6)-(x-2)=x^2(2x+3)(x-2)-(x-2)=(x-2)[x^2(2x+3)-1]=(x-2)(2x^3+3x^2-1)=(x-2)[(2x^3+2x^2)+(x^2-1)]=(x-2)[2x^2(x+1)+(x+1)(x-1)]=(x-2)(x+1)(2x^2+x-1)=(x-2)(x+1)(2x-1)(x+1)=(x+1)^2...

4x4 + 1 =? Factorization
The fourth power of 4x + 1

4x^4+1
=4x^4+4x^2+1-4x^2
=(2x^2+1)^2-4x^2
=(2x^2+1+2x)(2x^2+1-2x)
=(2x^2+2x+1)(2x^2-2x+1)

Factorization of 4x4-3x2 + 9

4x4-3x2+9
=(2x²)²+2*(2x²)*3+3²-15x²
=(2x²+3)²-(√15x)²
=(2x²-√15x+3)(2x²+√15x+3)

Factorization 2x3-13x2 + 3
Three and two after X are exponents.

2x³-13x²+3=2x³-x²-(12x²-3)=x²(2x-1)-3(4x²-1)=(2x-1)*[x²-3(2x+1)]=(2x-1)*(x²-6x-3)

Factorization of 1 / 2x ^ 2 + 2x-1 + 1 / 2x ^ 2-2x

One part x plus one times one part x minus one

Factorization. (1) x4-1998x2 + 1999x + 1998 (2) x3-3x2-13x + 15

(1) modify x4-1998x2 + 1999x + 1998
X4-1998x2+1999x-1998
=x^4+x-1998 (x²-x+1)
=x(x+1)(x²-x+1)-1998(x²-x+1)
=(x²-x+1)(x²+x-1998)
（2） x3-3x2-13x+15
=x³-x²-(2x²+13x-15)
=x²(x-1)-(2x+15)(x-1)
=(x-1)(x²-2x-15)
=(x-1)(x+3)(x-5)

Factorization in real numbers: X4 + x3-3x2-4x-4=______ ．

X4 + x3-3x2-4x-4 = X4 + X3 + x2-4x2-4x-4 = X2 (x2 + X + 1) - 4 (x2 + X + 1) = (x2-4) (x2 + X + 1) = (x + 2) (X-2) (x2 + X + 1)

X4-3x2 + 1 factorization of 4 and 2 is fast

x^4-2x²+1
=x^4-2x²+1-x²
=(x²-1)²-x²
=(x²-1+x)(x²-1-x)

Factorization (x + 3) (x ^ 2-1) (x + 5) - 20
We haven't learned so much,

(x + 3) (x ^ 2-1) (x + 5) - 20 = x ^ 4 + 8x ^ 3 + 14x ^ 2-8x-35 let (x + 3) (x ^ 2-1) (x + 5) - 20 be decomposable, where (x + a) (x + b) (x + C) (x + D) = x ^ 4 + 8x ^ 3 + 14x ^ 2-8x-35 a + B + C + D = 8 AB + BC + CD + ad = 14 ABC + BCD + ACD + abd = - 8 ABCD = - 35, and then calculate the values of a, B, C, D

Factorization: (1) 758-258 square. (3) 169 (a-b) square-196 (a + b) square. (4) the fourth power of N + 1-A and n-1b of A

1 （758+258）（758-258）
2 [13(a-b)-14（a+b)][13(a-b)+14(a+b)]
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