Find the matrix X so that XA = B, where a = [1 1; 2 1; - 1 1 2], B = [1 2 1; - 1 0 1]

Find the matrix X so that XA = B, where a = [1 1; 2 1; - 1 1 2], B = [1 2 1; - 1 0 1]

(A^T,B^T) =1 2 -1 1 -11 1 1 2 01 1 2 1 1r1-r2,r3-r20 1 -2 -1 -11 1 1 2 00 0 1 -1 1r1+2r3,r2-r30 1 0 -3 11 1 0 3 -10 0 1 -1 1r2-r10 1 0 -3 11 0 0 6 -20 0 1 -1 1-->1 0 0 6 -20 1 0 -3 10 0 1 -1 1X=6 -3 -...

Let x satisfy XA = B, where a = (21-1,21 0,11 1), B = (1-21,01-1), then x = ()

This is a matrix equation. The direct way is to find the inverse matrix of a first, and then multiply both sides of the equation by the inverse matrix of a at the same time to get the answer (if a is an invertible matrix, it is found that this condition a satisfies)

A = (1 - 21 - 1), B = (1 23 4 56), XA = B, find the matrix X
A=（1 -2,1 -1），B=（1 2,3 4,5 6）

A^(-1)=1/|A|A*=(-1 -2,-1 1)
X=BA^(-1)=
(1,2)*(-1 2)
(3,4) (-1 1)
(5,6)
=
(1 4)
(1 10)
(1 16)