Factorization A2 + (a + 1) 2 + A2 (a + 1) 2

Factorization A2 + (a + 1) 2 + A2 (a + 1) 2


a^2+(a+1)^2+[a(a+1)]^2
=[a-(a+1)]^2+2a(a+1)+[a(a+1)]^2
=1+2a(a+1)+[a(a+1)]^2
=[a(a+1)+1]^2 
=[a^2+a+1]^2



Factorization of (A2 + A + 1) (A2 + A + 2) - 12


(a2+a+1)(a2+a+2)-12=(a²+a)²+2(a²+a)+(a²+a)+2-12=(a²+a﹚²+3(a²+a)-10(a²+a+5)(a²+a-2)=(a²+a+5)(a+2)(a-1)



Factorization of a2-4b2 + A + 2B + 4bc-c2-c
The following 2 refers to the second power, thank you!