因式分解a2+(a+1)2+a2(a+1)2

因式分解a2+(a+1)2+a2(a+1)2


a^2+(a+1)^2+[a(a+1)]^2
=[a-(a+1)]^2+2a(a+1)+[a(a+1)]^2
=1+2a(a+1)+[a(a+1)]^2
=[a(a+1)+1]^2 ;
=[a^2+a+1]^2



(a2+a+1)(a2+a+2)-12因式分解


(a2+a+1)(a2+a+2)-12=(a²;+a)²;+2(a²;+a)+(a²;+a)+2-12=(a²;+a)²;+3(a²;+a)-10(a²;+a+5)(a²;+a-2)=(a²;+a+5)(a+2)(a-1)



a2-4b2+a+2b+4bc-c2-c因式分解
後面的2是指二次方,謝謝!