If the natural numbers P, P + 10 and P + 14 are prime numbers, how many arrays (P, P + 10 and P + 14) are there? If the natural numbers P, P + 10 and P + 14 are prime numbers, then how many numbers (P, P + 10 and P + 14) are there?

If the natural numbers P, P + 10 and P + 14 are prime numbers, how many arrays (P, P + 10 and P + 14) are there? If the natural numbers P, P + 10 and P + 14 are prime numbers, then how many numbers (P, P + 10 and P + 14) are there?

When p = 3N + 1, P + 14 = 3N + 15 = 3 (n + 5), not prime
When p = 3N + 2, P + 10 = 3N + 12 = 3 (n + 4), not prime
When p = 3N, only when n = 1, P = 3 is prime, and P + 10 = 13, P + 14 = 17 are prime
So there's only one P, which is 3

The fractional unit of 7 out of 8 is 1 out of 8. Adding a few such fractional units is the smallest prime number
A rectangular piece of paper 24 cm long and 18 cm wide should be divided into small squares of equal size with no surplus. At least it can be divided into ()
A 6, B 9, C 12, D 15

The smallest prime is 2,2-7 / 8 = 9 / 8
The fractional unit of 7 / 8 is 1 / 8, and adding 9 such fractional units is the smallest prime number
The greatest common divisor of 24 and 18 is 6,
A 24 cm long, 18 cm wide rectangular paper should be divided into small squares of equal size, and there is no surplus. At least it can be divided into (a)

How many units of 7 out of 12 are the smallest prime numbers?

Adding 17 such fractional units is the smallest prime number