On the equation of X, the square of X-2 (M + 2) x + (the square of m-1) = 0 (1) When m is a real number, the equation has two positive real roots (2) When m is a real number, the equation has a positive real root and a negative real root

According to the meaning of the title
x1+x2=2(m+2)>0
x1x2=m²-1>0
b²-4ac=4(m+2)²-4(m²-1)>=0
∴ -2

It is known that the root of the square of the equation x-3x + m is twice that of the other root, M = (), and the root of the original equation is ()

Weida theorem
x1+x2=3
x1x2=m
2 times, then x2 = 2x1
So X1 + x2 = 3x1 = 3
x1=1,x2=2
m=x1x2=2
M = (2), the roots of the original equation are (1 and 2)

The sixth power of (a + b) & #178; × (a + b)
=(2 + 6) power of (a + b)
=The eighth power of (a + b)