Factorization: (1) the square of 2005-10 times the square of 2005 + 25 (2) 7.77-2.23

Factorization: (1) the square of 2005-10 times the square of 2005 + 25 (2) 7.77-2.23

: (1) square of 2005 - 10 times 2005 + 25（
Original formula = 2005 & sup2; - 2 × 5 × 2005 + 5 & sup2;
=（2005-5）²
=4000000
2) 7.77 square - 2.23 square
Original formula = (7.77 + 2.23) (7.77-2.23)
=10×5.54
=55.4

(minus 3) square times [10 minus 4 times (root 3 plus 2)] plus 36 times root 3

I'll answer for you according to my understanding
(- 3) square * (10-4 * √ 3 + 2) + 36 * √ 3
=
9*（10-4√3-8）+36√3
=90-36√3-72+36√3
=18

What is the number whose square equals 0.36?

It should be ± 0.6

If there are two intersections between the parabola y = 2x2 + X + C and the coordinate axis, the value of the letter C satisfies the following conditions___ ．

∵ parabola y = 2x2 + X + C has two intersections with the coordinate axis. ① substitute (0, 0) into the analytical formula to get C = 0; ② △ = 1-8c = 0 to get C = 18. So the answer is: C = 18, C = 0

It is known that the coordinates of the image vertex of the square of y = x + BX + C are (- 2,3), and the distance between the image and the two intersections of X axis is 4

Y = x & # 178; + BX + C = (x + B / 2) &# 178; + C-B & # 178 / 4, vertex coordinates (- B / 2, C-B & # 178 / 4)
So - B / 2 = - 2, B = 4
C-B & # / 4 = 3, B = 4 into C = 7
The analytic expression of this function y = x & # 178; + 4x + 7 = (x + 2) &# 178; + 3 has no intersection with X axis

The image of function y = - 2x + 3x + m has two different intersection points with X axis

b^2-4ac>0
3^2-4*m*(-2)>0
m>-9/8

If the intersection of the line y = 2x + 3-m and the Y axis is above the X axis, then the value range of M is___ ．

∵ the intersection of the line y = 2x + 3-m and the y-axis is above the x-axis, ∵ the intersection of the function and Y is on the positive half axis of the y-axis, ∵ 3-m > 0, the solution is m < 3. So the answer is: m < 3

If the intersection of the line y = 2x + 3-m and the Y axis is above the X axis, then the value range of M is___ ．

∵ the intersection of the line y = 2x + 3-m and the y-axis is above the x-axis, ∵ the intersection of the function and Y is on the positive half axis of the y-axis, ∵ 3-m > 0, the solution is m < 3. So the answer is: m < 3

Original proposition: all quadratic equations have real solutions
Write his converse proposition, negative proposition, converse proposition and judge the true and false, and write the negative form of all false propositions

Write the original proposition in the form of if P, then Q
Original proposition: if an equation is quadratic, then the equation has real number solution
Inverse proposition: if an equation has a real solution, then the equation is quadratic
No proposition: if an equation is not quadratic, then the equation has no real solution
Inverse no proposition: if an equation has no real solution, then the equation is not quadratic
All false propositions
The negative form of the original proposition: not all quadratic equations have real solutions
Inverse proposition: Equations with real solutions are quadratic equations
Negative form of inverse proposition: Equations with real number solutions are not all quadratic equations
The negative form of no proposition: if an equation is not quadratic, then the equation may not have no real solution
The negative form of the inverse negative proposition: if an equation has no real solution, then the equation is not necessarily quadratic

It is known that the following three equations x2 + 4ax-4a + 3 = 0, X2 + (A-1) x + A2 = 0, and X2 + 2ax-2a = 0 have at least one real root, so the value range of real number a can be obtained

Assuming that no equation has real roots, the solution of 16a2-4 (3-4A) < 0 (1) (A-1) 2-4a2 < 0 (2) 4a2 + 8A < 0 (3) (5 points) is: − 32 < a < - 1 (10 points), so the value range of a with real roots of at least one of the three equations is: {a | a ≥ - 1 or a ≤ - 32}