Factorization 3 (X-2) = x (X-2)

Factorization 3 (X-2) = x (X-2)

3(x-2)=x(x-2); 3(x-2)-x(x-2) =0; (x-2)(3x-6-x)=0; (x-2)(2x-6)=0; 2(x-2)(x-3)=0; x-2=0;x=2; x-3=0;x=3

Factorization of (x ^ 2 minus 2x) minus 2 (x ^ 2 minus 2x) minus 3

There's something wrong with the problem. If there's no problem, the one upstairs is right, but it's not factorization
I think the first x ^ 2-2x should be squared
Take x ^ 2 minus 2x as a whole, a
Original formula = a ^ 2-2a-3 = (A-3) (a + 1) = (x ^ 2-2x-3) (x ^ 2-2x + 1) = (x-3) (x + 1) [(x-1) ^ 2]

Factorization (2x + 3) ^ 2-9 (x-1) ^ 2

(2x+3)^2-9(x-1)^2
=(2x+3)^2-(3x-3)^2
=(2x+3+3x-3)(2x+3-3x+3)
=-5x(x-6)