1. The left-hand factorization of equation (1-2x) &# 178; - 3 = 0 is (1-2x) &# 178; = 5 2. The univariate quadratic equation (x + 6) ² = 5 can be transformed into two quadratic equations, one of which is x + 6 = root 5, then the other is () 3. If X1 and X2 are the two roots of the equation x & # 178; = 4, then the value of X1 + X2 is ()

1. The left-hand factorization of equation (1-2x) &# 178; - 3 = 0 is (1-2x) &# 178; = 5 2. The univariate quadratic equation (x + 6) ² = 5 can be transformed into two quadratic equations, one of which is x + 6 = root 5, then the other is () 3. If X1 and X2 are the two roots of the equation x & # 178; = 4, then the value of X1 + X2 is ()

1. The left factorization of equation (1-2x) &# 178; - 3 = 0 ((1-2x-radical 3) (1-2x + radical 3)). 2. The univariate quadratic equation (x + 6) &# 178; = 5 can be transformed into two quadratic equations, one of which is x + 6 = radical 5, then the other is (x + 6 = - radical 5). 3

The factorization method is used to solve the equation x ^ 2-2 (√ 3 - √ 5) x + 4 √ 15 = 0, and the left side of the equation is decomposed into
X ^ 2-2 (√ 3 + √ 5) x + 4 √ 15 = 0, it's a plus, sorry for the wrong number

Are you sure your equation is OK?
You can't decompose it. Just look at the change of symbol. Pay attention to the change of symbol
If x ^ 2-2 (√ 3 + √ 5) x + 4 √ 15 = 0,
It is decomposed into (X-2 √ 3) (X-2 √ 5) = 0
If x ^ 2-2 (√ 3 - √ 5) x-4 √ 15 = 0,
It is decomposed into: (X-2 √ 3) (x + 2 √ 5) = 0

Factorization of the fourth power of a multiplied by the fourth power of B minus 16

Multiply the fourth power of a by the fourth power of B minus 16
=(a²b²)²－4²
=(a²b²＋4)(a²b²－4)
=(a²b²＋4)(ab＋2)(ab－2)