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xがx0になると、f'(x0)は[f(x)-f(x0)]/(x-x0)に近似します。 f(x)=f(x0)+f'(x0)(x-x0)を取得します。 この問題:f(x)=3√x,x=7.9,x0=8,f'(x)=1/3x^(-2/3)を上式に代入すると、 f(7.9)=2-0.1*(1/3)*(1/4)
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