3 / 2 power of 36

3 / 2 power of 36

3 / 2 root of 36
=The third power of the square root of 36
=Cube of 6
=216

(36 / 49),

3 / 2 power of (36 / 49)
=The third power of (6 / 7)
=216/343

What is the 36th power of 2?

2^36
=16^9
=4096^3
=68719476736

The fourth power of X - × = (xsquare + 4) (x + 2) (x - ×) the number of ×, × in the formula can be A.8, 1 B.16, 2 c.24, 3 d.64,

B
Square difference formula
X^4-16=(X^2+4)*(X^2-4)=(X^2+4)(X+2)(X-2)

Calculate the - 1 power of [- 1 / 4] + - 1 power of [- 2] + 0 power of [- 5] - [1 / 2] - 2

The original solution = - 4 + (1 / - 2) × 1-1 / 2-2
=-4-1/2-1/2-2
=-4-1-2
=-7

Calculate the 5th power of [- 1 / 4] times the 3rd power of [1 / 4] times the 2nd power of [- 1 / 4]

How to multiply the 12th power of 2 by the 12th power of 5?

It's the 12th power of (2 * 5), that's the 12th power of 10

Calculate the power of [2 times 10 to the fourth power] divided by the power of [- 2 times 10 to the third power] multiplied by [0.5 times 10 to the second power]
Calculate the third power of [2 times 10 to the fourth power] divided by the second power of [- 2 times 10 to the third power] multiplied by the second power of [0.5 times 10 to the second power]

Original formula = 3 power of 2 * 12 power of 10 (2 power of 2 * 6 power of 10) * (2-2 power of 2 * 4 power of 10)
=6 power of 2 * 10 - 2 power of 2 * 10 - 4 power of 10
=- 1 power of 2 * 10 power of 10
=The 10th power of 0.5 * 10
=The 9th power of 5 * 10

The 13th power of (2x-y) is divided by the 2nd power of [(2x-y) to the 3rd power of [(y-2x) to the 2nd power], where x = 2 and y = - 1

(2x－y)^13÷[(2x－y)^3]^2÷[(y－2x)^2]^3
＝(2x－y)^13÷(2x－y)^6÷{[-(2x－y)]^2}^3
＝(2x－y)^7÷[(2x－y)^2]^3
＝(2x－y)^7÷(2x－y)^6
＝2x－y
＝2×2－(-1)
＝4＋1
＝5

2X (- 5) + 2 to the third power - 3 divided by 1 / 2

The original formula is × (- 2;?) + 2
=2×(-5)+8-3×2
=-10+8-6
=-8