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x+|2x+y|=10 x-2y=8 x-2y=8得x=8+2y x=8+2yをx+|2x+y|=10 8+2y+|2(8+2y)+y|=10 解のy=-2 y=-2をx=8+2yに代入する 解得x=4 だからx=4 y=-2
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