If x = - 9 is equation 1 / 3x + | m | = - 1, then M = ()

If x = - 9 is equation 1 / 3x + | m | = - 1, then M = ()


Substituting x = - 9, we get - 3 + | m | = - 1
|m|=2
So m = 2 or M = - 2



Solution of equation 7 × 3x / (9 ^ X-2) = 2


The solution is 7 × 3 ^ X / (9 ^ X-2) = 2
7 × 3 ^ x = 2 (9 ^ X-2)
That is, 2 × 9 ^ X-7 × 3 ^ x-4 = 0
That is, (2 × 3 ^ x + 1) (3 ^ x-4) = 0
From 2 × 3 ^ x + 1 > 0
So 3 ^ x-4 = 0
The solution is x = log3 (4)



3x^2-6x=360 x=?


3x^2-6x=360
Divide by 3 x ^ 2-2x = 120
Finishing x ^ 2-2x-120 = 0
Cross phase multiplication results in (X-12) (x + 10) = 0
The solution is x = 12 or x = - 10



3x of 5 divided by 1 of 6 = 2 of 3


3x of 5 divided by 1 of 6 = 2 of 3
3x of 5 = 2x of 3, 1 of 6
3/5x=1/9
x=5/27



(3x-1)(4x+5)


Original formula = 3x (4x + 5) - 1 * (4x + 5)
=12x²+15x-4x-5
=12x²+11x-5



1/4x-5%x=4.8
Why users are jswenli's direct solution: 0.2x = 4.8


1/4x-5%x=4.8
0.2X=4.8
X=4.8/0.2
X=24



How to solve 12.8-4x = 6


12.8-6=4x
x=6.8/4
x=1.7



How to solve x-4x / 7 = 10 / 7


(1-4/7)x=10/7
3x/7=10/7
3x=10
x=10/3



Solution ratio: 2.4x-x = 7


This is the scale? Equation. 1.4x = 7 gives 5



Solving x ^ 2 + 4x-12 = 0 with formula


x^2+4x=12
x^2+4x+4=12+4=16
(x+2)^2=(±4)^2
x+2=±4
x=-2±4
x1=2,x2=-6