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2つの方程式x²+ax+b=0とx²+bx+a=0が唯一の公解を持っている場合、a+b=? ax+bx-a=0 (a-b)x+(a-b)=0 (a-b)(x-1)=0 だからx=1 だからx&sup2、+ax+b=0 1+a+b= すなわちa+b=-1
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