When a railway bridge is 1000m long and a train with length of AM passes through the bridge, the speed of the train is measured to be 1 & nbsp; min from the beginning to the end of the bridge______ ．

When a railway bridge is 1000m long and a train with length of AM passes through the bridge, the speed of the train is measured to be 1 & nbsp; min from the beginning to the end of the bridge______ ．

Suppose the speed of the train is v m / min. v = 1000 + A1 = 1000 + A, so the answer is: (1000 + a) m / min

An iron bridge is 1000 meters long. A train passes through the bridge. It takes one minute for the train to get on the bridge and then completely cross the bridge. The time for the whole train to be completely on the bridge is 40 seconds (from the rear of the train to the front of the train about to get off the bridge). How about the speed and length of the train?

1 minute = 60 seconds, all pass: S1 = l bridge + L, T1 = 60s, all on the bridge: S2 = l bridge - L, T2 = 40s, suppose the speed of the train is v m / s, the length of the train is l m, then 60s × v = 1000m + l40s × v = 1000m − L, the solution is: v = 20m / s, l = 20m

The length of a railway is 1000m. There is a train passing through the bridge. It takes 1min for the train to get on the bridge and pass the bridge completely
The time of the whole train completely on the bridge is 40s. Find the speed and length of the train. Do it with binary linear equation

(1000+L)/V=1x60
(1000-L)/V=40
L=200m
V=20m/s

It is known that the length of a railway bridge is 1000m. First, a train passes through the bridge. It takes 30 seconds for the train to get on the bridge and pass the bridge completely. The whole train is on the bridge
Municipal Construction Commission 20 seconds, the speed and length of the ball train?
The time is 20 seconds. How long is the train?

You can set up equations
Let the length of the train be x and the speed be y
If the tail of a train is regarded as a point, it can be listed as follows: x + 1000 = 30y
Similarly, the equation of "the whole car is on the bridge" is: 1000-x = 20Y
From the formula: x = 30y-1000
Substituting x = 30y-1000 into formula 2, we get 1000-30y + 1000 = 20Y
The solution is y = 40
By substituting y = 40 into formula (1), we get the following result:
x+1000=1200
The solution is: x = 200
A: (omitted)

It took 23 seconds for a train to cross a 450 meter long bridge and 8 seconds for a worker standing beside the railway. What's the speed and length of the train

First, the length of the car is l, the speed is v. s = 450 meters, T1 = 23 seconds, T2 = 8 seconds
From the meaning of the title
L+S=Vt1
Vt2=L
You can get it by substituting the data
V = 30 m / s, l = 240 m

It takes 22 seconds for a train to pass the 82 meter long railway bridge. If the speed of the train doubles and it takes 50 seconds to pass the 706 meter long railway bridge, how long is the train?

[(706-82) / (50 × 2-22)] × 22-82, = 8 × 22-82, = 94 meters. A: the length of the train is 94 meters

A 450 meter long train with a speed of 1200 m / min takes 1. How long is the bridge?

1200x1.5-450 = 1350m

It takes 22 seconds for a freight train to pass the 82 meter long railway bridge. If the speed is doubled, it takes only 50 seconds to pass the 706 meter long railway bridge. What is the original speed of the train?
Any method is OK, the process had better be clear, so that I can understand

Let the original velocity be X
（22x-82+706）/50=2x
22x-82+706=100x
78x=624
x=8

A bridge has a total length of 7300m and a train has a total length of 200m. If the train passes through the bridge at a uniform speed of 15mgs, the train will leave after passing the bridge
Start to accelerate, pass 4km distance in 3min time, find out the average speed in this 3min time is kmgh

After passing 4km in 3min (0.05h), the average speed is 4 / 0.05 = 80km / h

The 200m long train passes through the 1.6km long bridge at a constant speed of 120s, and the running speed of the train is ()
A. 15m/sB. 11.7m/sC. 1.7m/sD. 13.3m/s

The actual distance of the train s = 1600m + 200m = 1800m, the actual speed v = st = 1800m120s = 15m / s