How much speed does it take for a train to cross the railway bridge in 160m / S?

How much speed does it take for a train to cross the railway bridge in 160m / S?

From the meaning of the title
T = s total / v = (s Car + s Bridge) / v = (160m + 1440m) / 36 / 3.6 m / S = 160S
Answer: ---
I wonder if you want to write what you know and what you want?

A 20 m long train passes through a 980 m long railway bridge at a speed of 36 km / h. how many seconds does it take for the train to cross the bridge?

The distance of the train is s = 20m + 980m = 1000m, the speed is v = 36km / h = 10m / s, the crossing time of the train is t = SV = 1000m, 10m / S = 100s; answer: the crossing time of the train is 100s

The tunnel is 550 meters long and a train carriage is 50 meters long. It is running at a constant speed of 36 km / h. The speed of a passenger in the carriage is 1 m / s. when the train passes through the tunnel, the time for the passenger to pass through the tunnel is at least ()
A. 5 seconds B. 50 seconds C. 55 seconds D. 60 seconds

V car = 36km / h = 36 × 13.6m/s = 10m / s, if the minimum time for passengers to pass through the tunnel is t, then the distance of people walking: s man = v Man T, the distance of train walking: s car = V car T, as shown in the following figure, s man + s car = l tunnel, that is: 1m / s × T + 10m / s × t = 550m, the solution is: T = 50s. S man = V man, t = 1m / s × 50s = 50m

A 180m long train passes through a tunnel with a length of 1020m at the speed of 36km / h. (1) how long does it take for the train to pass through the tunnel? (2) how long does it take for the train to run in the tunnel?

36km/h=10m/s
（1）
It takes time
=（1020+180）÷10
=1200÷10
=120 seconds
（2）
It takes time
=（1020-180）÷10
=840÷10
=8.4 seconds

A train runs at a uniform speed of 120km / h. passengers sitting at the window see a 210m long train coming through
When passengers pass through a window with a speed of 2103km / h, they can see the speed of the oncoming train is 2103km / h?
Why 252-120 instead of 252 + 120?

Because the relative speed of the oncoming train is 210 / 3 = 70m / S = 252km / h with passengers as the reference
When the ground is taken as the reference, the passenger speed is 120km / h
Therefore, when the ground is taken as the reference, the speed of the oncoming train is 252-120 = 132km / h

In the new railway of western development, there is a tunnel with a total length of 1500 meters. A train runs at a constant speed, starting from the train
In the newly built railway in the western development, there is a tunnel with a total length of 1500 meters. It takes 55 seconds for a train to pass through the tunnel, from the beginning of entering the tunnel to completely leaving the tunnel, while the time for the whole train in the tunnel is 45 seconds. Find the running speed of the whole length of the train. (binary linear equation solution)
Find out the whole scene of the train and the running speed of the train

Let the train speed be x m / s and the length of the train be y M. the agenda of the two yuan one time is as follows:
55X＝1500＋Y
45X＝1500—Y
The solution is: x = 30, y = 150

It is known that the length of a railway bridge is 800 meters. A train passes through the bridge. It takes 45 seconds for the train to get on the bridge and completely cross the bridge. The time for the whole train to be completely on the bridge is 35 seconds. How about the speed and length of the train?

Suppose the speed of the train is x m / s and the length of the train is y M. then 45x = 800 + y35x = 800 − y, the two equations add up to get: 80x = 1600, x = 20, substituting x = 20 into y = 100, x = 20Y = 100. Answer: the speed of the train is 20 m / s and the length is 100 m

A 200m long train takes 1min30s to cross a 1600m long bridge. What is the speed of the train?

(200 + 1600) △ 90 = 1800 △ 90 = 20 m / S

It takes 1.5min for a train to pass a 1600m long bridge at the speed of 72km / h. what is the length of the train
The speed of physics movement in the second grade of junior high school

v=72km/h=20m/s
L=vt=20m/s*90s=1800m
L1=L-L2=1800m-1600m=200m

It takes three minutes for a 300m long train to pass through the tunnel at a speed of 15m / s
(2) How long does it take for the passengers who sit still to feel a little dark?
(2) How long does it take for a stationary passenger to feel a little dark?

L = 300 m, v = 15 m / s, t = 3 min = 180 s
(1) If the tunnel length is set as s, the train passing through the tunnel will be affected
L＋S＝V* t
That is 300 + S = 15 * 180
The tunnel length is s = 2400m
(2) The time when a passenger who does not move on the train feels a little dark is the time when the passenger has just entered the tunnel and left the tunnel. Set it to t
Then t = s / v = 2400 / 15 = 160 seconds