There's a math problem like this, X2-A If and only if x = - 1, the value of the fraction is 0. If x = - 3, the fraction is meaningless. Try to find out X2+BX+C A B C value, Because I can't input the square of X, let's use x 2 instead, an eager mother

There's a math problem like this, X2-A If and only if x = - 1, the value of the fraction is 0. If x = - 3, the fraction is meaningless. Try to find out X2+BX+C A B C value, Because I can't input the square of X, let's use x 2 instead, an eager mother

Don't worry, it's not difficult
First, x = - 1 is substituted into the fraction, because the fraction value is 0, so 1. The fraction is meaningful, the denominator is not zero, 2. The numerator is 0
So 1-A = 0, a = 1
Then we substitute x = 1 into the fraction (the reason why we consider this value is that the numerator does not change, and the denominator only differs from the negative sign of B). Because just now it is if and only if, we know that when x = 1, it is not zero, but the numerator gets zero, so it means that the denominator is also zero, and the fraction is meaningless
From this, we can see that B = - 0 + 1 + C = 1
Then substitute x = - 3, the denominator part 9-A = 9-1 = 8, the fraction is meaningless, indicating that the denominator is zero, 9-3b + C = 0
LIANLI
B+C=-1
9-3B+C=0
You can figure out BC. You can figure it out by yourself~