Is there anyone who can do this math problem? The speed ratio of the two vehicles is known to be 4:5. After the two vehicles meet on the way, the speed of the truck increases by 20%, and the speed of the bus remains unchanged. After another four hours, the truck arrives at a, and the bus is 112 kilometers away from B. how many kilometers do a and B want to be away from each other?

Is there anyone who can do this math problem? The speed ratio of the two vehicles is known to be 4:5. After the two vehicles meet on the way, the speed of the truck increases by 20%, and the speed of the bus remains unchanged. After another four hours, the truck arrives at a, and the bus is 112 kilometers away from B. how many kilometers do a and B want to be away from each other?

Suppose the speed of passenger car is 4x. The speed of freight car is 5x before meeting and 6x after meeting
6X*4=4X*6.
So it took 6 hours to drive before meeting. The whole truck took 6 + 4 = 10 hours
5X*6=30X
4*4X=16X
30X-16X=14X=112
X=8
The distance is 8 * 4 * 10 + 112 = 432

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