There is a fulcrum O in two shoulder poles ab of the same length, OA ≠ ob, Ma = MX in Figure 1 and MB = MX in Figure 2. Find the value of MX A__________ o___ B | | | | mx mb A__________ o__ B | | | | ma mx Find what MX equals,

There is a fulcrum O in two shoulder poles ab of the same length, OA ≠ ob, Ma = MX in Figure 1 and MB = MX in Figure 2. Find the value of MX A__________ o___ B | | | | mx mb A__________ o__ B | | | | ma mx Find what MX equals,

This problem refers to how to correct the balance if it is a lever with unequal arms
In Figure 1, the pressure on the left disk is equal to the gravity of the object, which is MXG, the arm of force is OA, and the weight is MB. The pressure on the right disk is MBG, and the arm of force is ob. According to the balance condition of the lever, the weight is MB
MXG * OA = MB * ob, similarly, in Figure 2, MAG * OA = MX * ob
Comparing the two formulas, the left side is better than the left side, and the right side is better than the right side
mx=(ma*mb)ˆ1/2

As shown in the figure, a weight g is suspended at the B end, and the force F is applied at the a point to keep the lever in horizontal balance regardless of the self weight of the lever
A. Because OA is larger than ob, f is smaller than GB. The size of F may be larger than GC. Because the pull on point B is downward, the direction of F must be upward. D. when the lever is balanced, G × ob = f × OA must be satisfied

A. The arm of force of F may be less than ob, and F may be greater than g, so this option is wrong. The arm of force of B and F may be less than ob, and F may be greater than g, so this option is correct. C. when the lever is balanced, the two forces should make the lever rotate in the opposite direction around the fulcrum, and the direction of F should be downward at point a, so this option is wrong So this option is wrong. So select B

Use a 2-meter-long shoulder pole to carry heavy objects. The front end of the shoulder pole is hung with 30 kg objects, and the back end is hung with 20 kg objects. To balance the shoulder pole in a horizontal position, how far should the shoulder be from the front end? (G is 10N / kg)

Let the problem be X. according to the principle of lever balance, the formula is: 30x = 20 (2-x). X = 0.8