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5,0f(x)dx=1,0f(x)dx+4,1f(x)dx+5,4f(x)dx=1,0(x^3)dx+4,1(√x)dx+5,4(2^x-14)dx=(1/4)x^4,0+(2/3)x^(3/2)|4,1+[(2^x/ln2)-14x]|5,4=(1/4)(1-0)+(2/3)(8-1)+(32-16)/ln2...
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