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酸塩基対反応. Ca(OH)2+2HCl=CaCl2+2H2O
教科書の実験からわかる:違う液体沸点違う、同種の液体の沸点と気圧関係、気圧が増大し、沸点が上がる。 したがって、応答は減少し、上昇する
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