0

0

y=-[log₂(x^2+2)]²-log(1/4)(x^2+2)+5=-[log₂(x²+2)]²+1/2log₂(x^2+2)+5 설정 t=log&\#8322;(x²+2)∵x²≥0,x²+2≥2∴t=log₂(x²+2)≥log₂2=1∴y=-t...