∫(x^3-3x^2+4x-9)/(x^2+3)dx

∫(x^3-3x^2+4x-9)/(x^2+3)dx

(x^3-3x^2+4x-9)/(x^2+3)=x-3+x/(x^2+3)
원 식=8747 x dx-8747 x+8747 x/(x^2+3)dx
=x^2/2-3x+1/2∫d(x^2+3)/(x^2+3)
=x^2/2-3x+ln(x^2+3)/2+C