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As shown in the figure, in the pyramid p-abcd, the bottom surface ABCD is a square, the PD ⊥ plane ABCD, and PD = AB = 2, e is the midpoint of Pb 1. Calculate the tangent of the angle between the paint line PD and AE 2. Verification: EF vertical plane PBC 3. Find the cosine value of dihedral angle f-pc-b
Connect AC to BD at o point, then EO ∥ PD, so EO ⊥ surface ABCD, that is OE ⊥ Ao
It is not difficult to get OE = (1 / 2) PD = 1, Ao = √ 2
So: the tangent of angle AEO is √ 2,
That is to say, the tangent of the angle between PD and AE is √ 2
2. Where's the f?
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