The perimeter of parallelogram ABCD is 70, the distances AE and AF from vertex a to BC and CD are 10 and 15, respectively

The perimeter of parallelogram ABCD is 70, the distances AE and AF from vertex a to BC and CD are 10 and 15, respectively

The area of parallelogram ABCD can be:
BC×AE=CD×AF
∴BC/CD=AF/AE=15/10
∴CD=70/(2+2×15/10)=14
The area of parallelogram ABCD is:
CD×AF=14×15=210