In the square abcd-a1b1c1d1, P is a moving point in the side b1b1cc. If the distance from P to the straight line BC and c1d1 is equal, then the trajectory of the moving point P is? Why a parabola?

Analysis: from the vertical plane bb1c1c of line c1d1, it is found that | PC1 | is the distance from point P to line c1d1, then the moving point P satisfies the definition of parabola, and the problem is solved
From the meaning of the title, if the straight line c1d1 ⊥ plane bb1c1c, then c1d1 ⊥ PC1, that is, | PC1 | is the distance from point P to the straight line c1d1,
Then the distance from point P to line BC is equal to the distance from point C, so the trajectory of point P is a parabola

RELATED INFORMATIONS

1. In the cube abcd-a1b1c1d1, M is the midpoint of CC1. If P is on the plane of abb1a1 and satisfies ∠ pdb1 = ∠ mdb1, what is the trajectory of point P? The answer is hyperbola But I think the picture I draw also looks like a parabola Is there a curve? How can I draw only one
2. In the cube abcd-a1b1c1d1, M is the midpoint of CC1. If point P is on the plane of abb1a1 and satisfies ∠ pdb1 = ∠ mdb1, then the trajectory of point P is () A. Circle B. ellipse C. hyperbola D. parabola
3. A mathematical problem: let p be a point inside the square ABCD, and the distances from P to vertex a, B and C are 1, 2 and 3, respectively
4. P is a point inside the square ABCD. The distances from point P to vertex a, B and C are 1, 2 and 3 respectively. Find the side length of the square Using trigonometric function solution, there are two results under the solution. Why should 5-2 √ 2 be omitted?
5. Let p be a point in the square ABCD, and the distances from point P to vertex ABC are 1, 2 and 3 respectively
6. P is a point outside the parallelogram ABCD, and Q is the midpoint of PA
7. P is the point out of the plane of the parallelogram ABCD, and Q is the midpoint of PA
8. P is a point out of the plane of the parallelogram ABCD. Find a point E on PC to make the PA ‖ face be, and give the proof
9. P is a point outside the parallelogram ABCD, and Q is the midpoint of PA
10. The bottom surface of the pyramid p-abcd is a square with side length 1, and the side edge PA is perpendicular to the bottom surface ABCD. Moreover, PA = 2. If e is the midpoint of PA, we prove the plane BDE
11. As shown in the figure, in the cube abcd-a1b1c1d1, P is a moving point in the side bb1c1c. If the distance from P to the straight line BC and the straight line c1d1 is equal, the curve of the trajectory of the moving point P is () A. Straight line B. circle C. hyperbola D. parabola
12. The perimeter of parallelogram ABCD is 70, the distances AE and AF from vertex a to BC and CD are 10 and 15, respectively
13. As shown in the figure, in the pyramid p-abcd, the quadrilateral ABCD is a rectangle, the plane PCD ⊥ the plane ABCD, and M is the midpoint of PC
14. In a square pyramid p-abcd, the plane PCD is perpendicular to the plane ABCD, PC = PD = CD = 2, and the dihedral angle b-pd-c is calculated Urgent! It's a process
15. As shown in the figure, in the pyramid p-abcd, the bottom surface ABCD is a square, the PD ⊥ plane ABCD, and PD = AB = 2, e is the midpoint of Pb 1. Calculate the tangent of the angle between the paint line PD and AE 2. Verification: EF vertical plane PBC 3. Find the cosine value of dihedral angle f-pc-b
16. The difference between QA and QC
17. Two charges a and B are placed on the smooth insulating plane in vacuum, with the distance r between them. The charges are QA = + 9q, QB = + Q respectively, and another point charge QC is placed Just so that the three spheres are in equilibrium only under the action of their mutual electrostatic force, what kind of charge should QC carry, where should it be placed, and what is the amount of charge
18. What do QC, QA, QE and QD mean in quality inspection?
19. What is QC, QA, QE, and what is QB?
20. From a point m on the sphere with radius r, three pairs of perpendicular strings Ma, MB and MC of the leading sphere, then ma2 + MB2 + MC2 equals () A. R2B. 2R2C. 4R2D. 8R2